A neighboring EIGRP router fails. Its advertised distance (AD) to network 10.10.10.0 was 2 and the feasible distance (FD) was 3.Which route will be used to route packets destined for network 10.10.10.0 if the other routes have the following feasible and advertised distances respectively to the destination network?
When EIGRP loses it best route, called the successor route, it will then use a feasible successor route, if available, to route the packets to that destination. To be considered a feasible successor, the advertised distance, which is the neighboring router’s distance, needs to be less than the feasible distance, which is the local router’s own metric.
In this scenario, the feasible distance is 3. The only available feasible successors are the ones that have the advertised distance/feasible distance of 1/4 and 2/4.
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